Two Containers Mixing Puzzle

This is a slightly different type of a mixture problem from Dan Griller.

“Two containers A and B sit on a table, partially filled with water.  First, 40% of the water in A is poured into B, which completely fills it.  Then 75% of the water in B is poured into A, which completely fills it.  80% of the water in A is poured into B, which completely fills it.  Calculate the ratio of the capacity of container A to the capacity of container B, and the fraction of container A that was occupied by water at the start.”

See the Two Containers Mixing Puzzle

One thought on “Two Containers Mixing Puzzle

  1. Sanjay Godse

    A simple method for finding the ratio of capacities.

    75% of B is transferred to A to make A full.
    To make B full again, same quantity should be transferred from A to B. This is equivalent to 80% of A.

    Thus 75% of B is same as 80% of A. It implies that, the ratio of the two capacities is
    A/B=75/80=15/16

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